-sin^2+4cosx+1=0

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Solution for -sin^2+4cosx+1=0 equation:


Simplifying
-1sin2 + 4cosx + 1 = 0

Reorder the terms:
1 + 4cosx + -1in2s = 0

Solving
1 + 4cosx + -1in2s = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + 4cosx + -1 + -1in2s = 0 + -1

Reorder the terms:
1 + -1 + 4cosx + -1in2s = 0 + -1

Combine like terms: 1 + -1 = 0
0 + 4cosx + -1in2s = 0 + -1
4cosx + -1in2s = 0 + -1

Combine like terms: 0 + -1 = -1
4cosx + -1in2s = -1

Add 'in2s' to each side of the equation.
4cosx + -1in2s + in2s = -1 + in2s

Combine like terms: -1in2s + in2s = 0
4cosx + 0 = -1 + in2s
4cosx = -1 + in2s

Divide each side by '4osx'.
c = -0.25o-1s-1x-1 + 0.25in2o-1x-1

Simplifying
c = -0.25o-1s-1x-1 + 0.25in2o-1x-1

Reorder the terms:
c = 0.25in2o-1x-1 + -0.25o-1s-1x-1

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